2.Write the additive inverse of each of the following:
(i)$$\frac{2}8$$

(ii)$$\frac{-5}9$$

(iii)$$\frac{-6}{-5}$$

(iv)$$\frac{2}{-9}$$

(v)$$\frac{19}{-6}$$

We have additive inverse of a as a=-a .So, we have:

(i) Additive inverse of $$\frac{2}8 = \frac{-2}8$$

(ii)Additive inverse of $$\frac{-5}9 = -(\frac{-5}9)= \frac{5}9$$

(iii) we have $$\frac{-6}{-5}= \frac{6}5$$

∴ the additive inverse of $$\frac{6}5 =\frac{-6}5$$

(iv)We have $$\frac{2}{-9}=\frac{-2}9$$

∴ Additive inverse of $$\frac{-2}{9} = -(\frac{-2}9)= \frac{2}9$$

(v)We have $$\frac{19}{-6}=\frac{-19}6$$

∴ Additive inverse of $$\frac{-19}{6} = -(\frac{-19}6)= \frac{19}6$$