8.Is \(\frac{8}9\) the multiplicative inverse of \(-1\frac{1}8\)? Why or why not?

We have \(-1\frac{1}8=\frac{-9}{8}\)

Since multiplication inverse of \(\frac{8}9 is \frac{9}8 \) but not \(\frac{-9}8\)

Because, \(\frac { 8 }{ 9 } \times -1\frac { 1 }{ 8 } =\frac { 8 }{ 9 } \times \frac { -9 }{ 8 } =-1\neq 1\)

So, \(\frac{8}9 \) is not the multiplicative inverse of \(-1\frac{1}8\).