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Answer :
Here,we have 14y – 8 = 13
\(\Rightarrow\) 14y – 8 + 8 = 13 + 8 (adding 8 to both sides)
\(\Rightarrow\) 14y = 21
\(\Rightarrow\) 14y ÷ 14 = 21 ÷ 14 (dividing both sides by 14)
\(\Rightarrow\) y =\(\frac { 21 }{ 14 }\)
\(\Rightarrow\)y = \(\frac { 3 }{ 2 }\)
Thus, y = \(\frac { 3 }{ 2 }\) is the required solution.
Check:
Keepy = \(\frac { 3 }{ 2 }\) in the given solution
L.H.S=\(14y-8=14×\frac{3}{2}-8=7×3-8=21-8=13\)=R.H.S
Hence y = \(\frac { 3 }{ 2 }\) is the required solution.