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Answer :
Let the number be x
Condition 1: \(x-\frac{1}2\)
Condition 2: \((x-\frac{1}2) ×\frac{1}2\)
Condition 3: \(x-\frac{1}2) ×\frac{1}2 =\frac{1}8\)
\(\Rightarrow (x-\frac{1}2) ×\frac{1}2 × 8=\frac{1}8×8\quad \)[multiplying both the sides by 8]
\(\Rightarrow (x-\frac{1}2) ×4=1\)
\(\Rightarrow 4x-\frac{1}2 ×4=1\quad \)[opening the brackets]
\(\Rightarrow 4x-2=1\)
\(\Rightarrow 4x-2+2=1+2 \quad \)[adding 2 to both the sided]
\(\Rightarrow 4x=3\)
\(\Rightarrow 4x÷4= 3÷4\quad \)[dividing both the sides by 4]
\(\Rightarrow x=\frac{3}4\)
Thus, the required number is \(\frac{3}4\)