Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Given 5t – 3 = 3t – 5
\(\Rightarrow\) 5t – 3t – 3 = -5 (Transposing 3t to LHS)
\(\Rightarrow\)2t = -5 + 3 (Transposing -3 to RHS)
\(\Rightarrow\)2t = -2
\(\Rightarrow\) t = -2 ÷ 2
\(\Rightarrow\) t = -1
Hence, t = -1 is the required solution.
Checking:
5t – 3 = 3t – 5
Substitute t = -1 in the given equation, we have
LHS = 5t – 3 = 5 × (-1)-3 = -5 – 3 = -8
RHS = 3t – 5 = 3 × (-1) – 5 = -3 – 5 = -8
LHS = RHS
Hence, t = -1 is the required solution.