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Answer :
Given 2x – 1 = 14 – x
\(\Rightarrow\) 2x + x = 14 + 1 (Transposing x to LHS and 1 to RHS)
\(\Rightarrow\) 3x = 15
\(\Rightarrow\)x = 15 ÷ 3 = 5
Hence x = 5 is the required solution.
Checking:
2x – 1 = 14 – x
Substituting x = 5 in the given equation,we have,
LHS= 2x – 1 = 2 × 5 – 1 = 10 – 1 = 9
RHS = 14 – x = 14 – 5 = 9
LHS = RHS
Hence x = 5 is the required solution.