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Answer :
Given, 8x + 4 = 3(x – 1) + 7
\(\Rightarrow\) 8x + 4 = 3x – 3 + 7 (Solving the bracket)
\(\Rightarrow\)8x + 4 = 3x + 4
\(\Rightarrow\) 8x – 3x = 4 – 4 [Transposing 3x to LHS and 4 to RHS]
\(\Rightarrow\) 5x = 0
\(\Rightarrow\) x = 0 ÷ 5 [Transposing 5 to RHS]
or x = 0
Hence, x = 0 is the required solution.
Checking:
8x + 4 = 3(x – 1) + 7
Substituting x = 0 in the given equation, we have
8 × 0 + 4 = 3(0 – 1) + 7
\(\Rightarrow\) 0 + 4 = -3 + 7
\(\Rightarrow\) 4 = 4
LHS = RHS
Hence, x = 0 is the required solution.