6. 8x + 4 = 3(x – 1) + 7

Given, 8x + 4 = 3(x – 1) + 7
\(\Rightarrow\) 8x + 4 = 3x – 3 + 7 (Solving the bracket)

\(\Rightarrow\)8x + 4 = 3x + 4

\(\Rightarrow\) 8x – 3x = 4 – 4 [Transposing 3x to LHS and 4 to RHS]

\(\Rightarrow\) 5x = 0

\(\Rightarrow\) x = 0 ÷ 5 [Transposing 5 to RHS]

or x = 0

Hence, x = 0 is the required solution.

Checking:

8x + 4 = 3(x – 1) + 7

Substituting x = 0 in the given equation, we have

8 × 0 + 4 = 3(0 – 1) + 7

\(\Rightarrow\) 0 + 4 = -3 + 7

\(\Rightarrow\) 4 = 4

LHS = RHS

Hence, x = 0 is the required solution.