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Answer :
Given x = \(\frac { 4 }{ 5 } (x + 10)\)
\(\Rightarrow\) 5 × x = 4(x + 10) (Transposing 5 to LHS)
\(\Rightarrow\) 5x = 4x + 40 (Solving the bracket)
\(\Rightarrow\) 5x – 4x = 40 (Transposing 4x to LHS)
\(\Rightarrow\) x = 40
Thus x = 40 is the required solution.
Checking:
x = \(\frac { 4 }{ 5 }\) (x + 10)
Substituting x = 40 in the given equation, we have
40 = \(\frac { 4 }{ 5 } \)(40 + 10)
\(\Rightarrow\) 40 =\( \frac { 4 }{ 5 }\) × 50
\(\Rightarrow\) 40 = 4× 10
\(\Rightarrow\) 40 = 40
LHS = RHS
Hence x = 40 is the required solution.