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# 7. x =$$\frac { 4 }{ 5 } (x + 10)$$

Given x = $$\frac { 4 }{ 5 } (x + 10)$$
$$\Rightarrow$$ 5 × x = 4(x + 10) (Transposing 5 to LHS)

$$\Rightarrow$$ 5x = 4x + 40 (Solving the bracket)

$$\Rightarrow$$ 5x – 4x = 40 (Transposing 4x to LHS)

$$\Rightarrow$$ x = 40

Thus x = 40 is the required solution.

Checking:

x = $$\frac { 4 }{ 5 }$$ (x + 10)

Substituting x = 40 in the given equation, we have

40 = $$\frac { 4 }{ 5 }$$(40 + 10)

$$\Rightarrow$$ 40 =$$\frac { 4 }{ 5 }$$ × 50

$$\Rightarrow$$ 40 = 4× 10

$$\Rightarrow$$ 40 = 40

LHS = RHS

Hence x = 40 is the required solution.