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10.$$3m=5m-\frac { 8 }{ 5 }$$

Given that, $$3m=5m-\frac { 8 }{ 5 }$$
$$\Rightarrow 3m-5m=-\frac {8 }{ 5 } \quad$$[Transposing 5m to LHS]

$$\Rightarrow -2m=-\frac {8 }{ 5 }$$

$$\Rightarrow \frac{-2m}{-2}=\frac{-\frac {8 }{ 5 }}{-2}\quad$$[Dividing both the sides by -2]

$$\Rightarrow m=\frac {4}{ 5 }$$

Thus,$$m=\frac {4}{ 5 }$$ is the required solution

Checking:

Substituting $$m=\frac {4}{ 5 }$$ in the given equation, we have

LHS=$$3×\frac{4}5 =\frac{12}5$$

RHS=$$4×\frac{4}5 - \frac{8}5=\frac{20}5-\frac{8}5 =\frac{12}5$$

RHS=LHS

Hence,$$m=\frac {4}{ 5 }$$ is the required solution