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Answer :
Given that,
3(t – 3) = 5(2t + 1)
\(\Rightarrow\) 3t – 9 = 10t + 5 [Solving the brackets]
\(\Rightarrow\) 3t – 10t = 9 + 5 [Transposing 10t to LHS and 9 to RHS]
\(\Rightarrow\) -7t = 14
\(\Rightarrow\) t = -2[Transposing -7 to RHS]
Thus, t = -2 is the required solution.