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8. 15(y – 4) – 2(y – 9) + 5(y + 6) = 0


Answer :

Given that, 15(y – 4) – 2(y – 9) + 5(y + 6) = 0

\(\Rightarrow\)15y – 60 – 2y + 18 + 5y + 30 = 0 [Solving the brackets]

\(\Rightarrow\) 8y – 12 = 0

\(\Rightarrow\) 8y = 12 [Transposing 12 to RHS]

\(\Rightarrow\) y =\( \frac { 2 }{ 3 }\)

Hence, y = \(\frac { 2 }{ 3 }\) is the required solution.

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