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# 8. 15(y – 4) – 2(y – 9) + 5(y + 6) = 0

Given that, 15(y – 4) – 2(y – 9) + 5(y + 6) = 0

$$\Rightarrow$$15y – 60 – 2y + 18 + 5y + 30 = 0 [Solving the brackets]

$$\Rightarrow$$ 8y – 12 = 0

$$\Rightarrow$$ 8y = 12 [Transposing 12 to RHS]

$$\Rightarrow$$ y =$$\frac { 2 }{ 3 }$$

Hence, y = $$\frac { 2 }{ 3 }$$ is the required solution.