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Answer :
Given that, \(\frac { 8x-3 }{ 3x } =2\)
\(\Rightarrow \frac { 8x-3 }{ 3x } = \frac { 2 }{ 1 }\)
\(\Rightarrow 8x – 3 = 2 × 3x \quad \)[Cross-multiplication]
\(\Rightarrow 8x – 3 = 6x\)
\(\Rightarrow 8x – 6x = 3\) [Transposing 6x to LHS and 3 to RHS]
\(\Rightarrow 2x = 3\quad \)[Dividing both the sides by 2]
\(\Rightarrow x = \frac { 3 }{ 2 }\)