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3.\(\frac { z }{ z+15 } =\frac { 4 }{ 9 }\)


Answer :

Given that, \(\frac { z }{ z+15 } =\frac { 4 }{ 9 }\)
\(\Rightarrow 9z = 4 (z + 15)\quad \) [Cross-multiplication]

\(\Rightarrow 9z = 4z + 60 \quad \)[Solving the bracket]

\(\Rightarrow 9z – 42 = 60 \)

\(\Rightarrow 5z = 60\)

\(\Rightarrow z = 12\)

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