Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Given that, \(\frac { z }{ z+15 } =\frac { 4 }{ 9 }\)
\(\Rightarrow 9z = 4 (z + 15)\quad \) [Cross-multiplication]
\(\Rightarrow 9z = 4z + 60 \quad \)[Solving the bracket]
\(\Rightarrow 9z – 42 = 60 \)
\(\Rightarrow 5z = 60\)
\(\Rightarrow z = 12\)