4. \(\frac { 3y+4 }{ 2-6y } =\frac { -2 }{ 5 }\)

Given that, \(\frac { 3y+4 }{ 2-6y } =\frac { -2 }{ 5 }\)
\(\Rightarrow 5(3y + 4) = -2(2 – 6y)\quad \) [Cross-multiplication]

\(\Rightarrow 15y + 20 = -4 + 12y \quad \)[Solving the bracket]

\(\Rightarrow 15y – 12y = -4 – 20\quad \) [Transposing 12y to LHS and 20 to RHS]

\(\Rightarrow 3y = -24\quad \) [Transposing 3 to RHS]

\(\Rightarrow y = -8\)