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Answer :

(i)Here, ABCD is a parallelogram.

\(∠B = ∠D\quad \) [Opposite angles of a parallelogram are equal]

\(∠D = 100^{\circ}\)

\(\Rightarrow y = 100^{\circ}\)

\(∠A + ∠B = 180^{\circ}\quad\) [Adjacent angles of a parallelogram are supplementary]

\(\Rightarrow z + 100^{\circ} = 180^{\circ}\)

\(\Rightarrow z = 180^{\circ} – 100^{\circ} = 80^{\circ}\)

\(∠A = ∠C\quad\) [Opposite angles of a parallelogram are equal]

\(x = 80^{\circ}\)

\(Hence, x = 80^{\circ}, y = 100^{\circ} and\; z = 80^{\circ}\)

(ii)We have PQRS as a parallelogram.

\(∠P + ∠S = 180^{\circ}\quad \) [Adjacent angles of parallelogram]

\(\Rightarrow x + 50^{\circ} = 180^{\circ}\)

\(\Rightarrow x = 180^{\circ} – 50^{\circ} = 130^{\circ}\)

\(Now, ∠P = ∠R\quad\)[Opposite angles are equal]

\(\Rightarrow x = y\)

\(\Rightarrow y = 130^{\circ}\)

\(Also, y = z\quad\) [Alternate angles]

\(\Rightarrow z = 130^{\circ}\)

\(Hence, x = 130^{\circ}, y = 130^{\circ} and z = 130^{\circ}\)

(iii) Here we have, ABCD as a rhombus because diagonals intersect at \(90^{\circ} \)

\(So, x = 90^{\circ}\)

So,now in ∆OCB we have,

\(x + y + 30^{\circ} = 180^{\circ}\quad \) [Angle sum property]

\(\Rightarrow 90^{\circ} + y + 30^{\circ} = 180^{\circ}\)

\(\Rightarrow y + 120^{\circ} = 180^{\circ}\)

\(\Rightarrow y = 180^{\circ} – 120^{\circ} = 60^{\circ}\)

\(y = z \quad \)[Alternate angles]

\(\Rightarrow z = 60^{\circ}\)

\(Hence, x = 90^{\circ}, y = 60^{\circ} and z = 60^{\circ}\)

(iv) ABCD is a parallelogram

∠A + ∠B = 180^{\circ} (Adjacent angles of a parallelogram are supplementary)

\(\Rightarrow x + 80^{\circ} = 180^{\circ}\)

\(\Rightarrow x = 180^{\circ} – 80^{\circ} = 100^{\circ}\)

\(Now, ∠D = ∠B\quad \) [Opposite angles of a parallelogram are equal]

\(\Rightarrow y = 80^{\circ}\)

\(Also, z = ∠B = 80^{\circ}\quad\) (Alternate angles)

\(So, x = 100^{\circ}, y = 80^{\circ} and z = 80^{\circ}\)

(v) In this case we have ABCD as a parallelogram.

\(∠D = ∠B \quad\)[Opposite angles of a parallelogram are equal]

\(y = 112^{\circ}\)

\(x + y + 40^{\circ} = 180^{\circ}\quad\) [Angle sum property]

\(\Rightarrow x + 112^{\circ} + 40^{\circ} = 180^{\circ}\)

\(\Rightarrow x + 152^{\circ} = 180^{\circ}\)

\(\Rightarrow x = 180^{\circ} – 152^{\circ} = 28^{\circ}\)

\(z = x = 28^{\circ} \quad \)[Alternate angles]

\(So\; we \;have, x = 28^{\circ}, y = 112^{\circ}, z = 28^{\circ}\).

- 1.Given a parallelogram ABCD. Complete each statement along with the definition or property used. (i) AD = ………… (ii) ∠DCB = ……… (iii) OC = ……… (iv) m?DAB + m∠CDA = ……..
- 3.Can a quadrilateral ABCD be a parallelogram if (i) \(∠D + ∠B = 180^{\circ}?\) (ii) AB = DC = 8 cm, AD = 4 cm and BC = 4.4 cm? (iii)\(∠A = 70^{\circ} and ∠C = 65^{\circ}?\)
- 4.Draw a rough figure of a quadrilateral that is not a parallelogram but has exactly two opposite angles of equal measure.
- 5.The measures of two adjacent angles of a parallelogram are in the ratio 3 : 2. Find the measure of each of the angles of the parallelogram.
- 6.Two adjacent angles of a parallelogram have equal measure. Find the measure of each of the angles of the parallelogram.
- 7.The adjacent figure HOPE is a parallelogram. Find the angle measures x, y and z. State the properties you use to find them.
- 8.The following figures GUNS and RUNS are parallelograms. Find x and y. (Lengths are in cm)
- 9.In the above figure both RISK and CLUE are parallelograms. Find the value of x.
- 10.Explain how this figure is a trapezium. Which of its two sides are parallel?
- 11.Find m∠C in below figure if \(\bar { AB } ∥ \bar { DC }\)
- 12.Find the measure of ∠P and ∠S if \(\bar { SP } ∥ \bar { RQ }\) in figure, is there any other method to find m∠P?)

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