9.In the above figure both RISK and CLUE are parallelograms. Find the value of x.

Here we have RISK and CLUE as two parallelograms.
\(∠1 = ∠L = 70^{\circ}\quad\) [Opposite angles of a parallelogram]

\(∠K + ∠2 = 180^{\circ}\)

Sum of adjacent angles is \(180^{\circ}\)

\(120^{\circ} + ∠2 = 180^{\circ}\)

\(∠2 = 180^{\circ} – 120^{\circ} = 60^{\circ}\)

In ∆OES we have,

\(∠x + ∠1 + ∠2 = 180^{\circ}\quad\) [Angle sum property]

\(\Rightarrow ∠x + 70^{\circ} + 60^{\circ} = 180^{\circ}\)

\(\Rightarrow ∠x + 130^{\circ} = 180^{\circ}\)

\(\Rightarrow ∠x = 180^{\circ} – 130^{\circ} = 50^{\circ}\)

Hence \(∠x = 50^{\circ}\)