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Answer :
Since AB ∥ DC and transversal BC intersects
them.So we have,
\(∠B + ∠C= 180^{\circ}\quad \)
[∵ Sum of interior angles is 180^{\circ}]
\(\Rightarrow 120^{\circ}+ ∠C =180^{\circ} \)
\(\Rightarrow ∠C = 180^{\circ}- 120^{\circ} = 60^{\circ}\)
Hence, \(m∠C =60^{\circ}\)