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Answer :
Construction:
Step 1: Draw a line segment OK = 5.5 cm.
Step 2: Draw an angle of any measure (let's say \(60^{\circ}\)) at K and cut an arc KA = 4.2 cm.
Step 3: Draw an arc with centre A and radius of 5.5 cm.
Step 4: Draw another arc with centre O and radius 4.2 cm to cut the previous arc at Y.
Step 5: Join AY and OY.
Hence we have OKAY as the required parallelogram.
No, it is not a unique parallelogram because the angle at K can be of any measure other than \(60^{\circ}\).