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Answer :
(i)An event of getting a number 6, i. e., if we obtain a slip having number 6 as an outcome out of total 10 slips
So favourable number of outcomes = 1
∴ required probability of getting a number 6 = \(\frac{1}{10}\)
(ii) Probability of getting a number less than 6 = \(\frac{5}{10}= \frac{1}2\) [∵ Numbers less than 6 are 1, 2, 3, 4, 5]
(iii) Probability of getting a number greater than 6 = \(\frac{4}{10}= \frac{2}5\) [∵ Number greater than 6 are 7, 8, 9, 10]
(iv) Probability of getting a 1-digit number = \(\frac{9}{10}\)
[∵ 1-digit numbers are 9, i.e. 1, 2, 3, 4, 5, 6, 7, 8, 9]