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Answer :
Out of the total 5 sectors, the pointer can stop at any of the sectors in 5 ways.
∴ Total number of outcomes = 5
There are 3 green sectors in the spinning wheel, out of which one can be obtained in 3 ways.
∴ Favourable number of outcomes = 3
So, the required probability for green sector= \(\frac { 3 }{ 5 }\)
Further, there are 4 ways to obtain a non-blue sector out of 4 non-blue present in the spinning wheel.
So, the required probability for non- blue sector = \(\frac { 4 }{ 5 } \)