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Answer :

Out of the total 5 sectors, the pointer can stop at any of the sectors in 5 ways.

∴ Total number of outcomes = 5

There are 3 green sectors in the spinning wheel, out of which one can be obtained in 3 ways.
∴ Favourable number of outcomes = 3

So, the required probability for green sector= \(\frac { 3 }{ 5 }\)

Further, there are 4 ways to obtain a non-blue sector out of 4 non-blue present in the spinning wheel.

So, the required probability for non- blue sector = \(\frac { 4 }{ 5 } \)

- 1.List the outcomes you can see in these experiments. (i) Spinning a wheel (ii) Tossing two coins together
- 2.When a die is thrown, list the outcomes of an event of getting (i) (a) a prime number (b) not a prime number (ii) (a) a number greater than 5 (b) a number not greater than 5
- 3. Find the (i) Probability of the pointer stopping on D in (Question 1-(a))? (ii) Probability of getting an ace from a well-shuffled deck of 52 playing cards? (iii) Probability of getting a red apple, (see figure below)
- 4.Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of: (i) getting a number 6? (ii) getting a number less than 6? (iii) getting a number greater than 6? (iv) getting a 1-digit number?
- 6.Find the probabilities of the events given in Question 2.

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