6.Find the probabilities of the events given in Question 2.

In a single throw of a die, we can get any one of the six numbers marked on its six faces. Therefore, the total number of outcomes = 6
(i) Let A denote the event “getting a prime number”. So,event A occurs if we obtain 2, 3, 5 as an outcome.

∴ Favourable number of outcomes = 3

Hence, P\(\left( A \right) =\frac { 3 }{ 6 } =\frac { 1 }{ 2 } \)

(ii) Let A denote the event “not getting a prime number”. So, event A occurs if we obtain 1, 4, 6 as an outcome.

∴ Favourable number of outcomes = 3

Hence, P\(\left( A \right) =\frac { 3 }{ 6 } =\frac { 1 }{ 2 }\)

(iii) The event “getting a number greater than 5” will occur if we obtain the number 6.

∴ Favourable number of outcomes = 1

Hence, the required probability = \(\frac { 1}{ 6 } \)

(iv) The event “getting a number not greater than 5” will occur if we obtain one of the numbers 1, 2, 3, 4, 5.

∴ Favourable number of outcomes = 5

Hence, required probability = \(\frac { 5 }{ 6 } \)