6.Using the given pattern, find the missing numbers.
\(1^2 + 2^2 + 2^2 = 3^2\)

\(2^2 + 3^2 + 6^2 = 7^2\)

\(3^2 + 4^2 + 12^2 = 13^2\)

\(4^2 + 5^2 + ….^2 = 21^2\)

\(5^2 + ….^2 + 30^2 = 31^2\)

\(6^2 + 7^2 + …..^2 = ……2\)


Answer :

According to the given pattern, we have the third number as the product of the first two numbers and fourth number is obtained after adding 1 to the third number.

\(4^2 + 5^2 + 20^2 = 21^2\)

\(5^2 + 6^2 + 30^2 = 31^2\)

\(6^2 + 7^2 + 42^2 = 43^2\)

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