Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Given, SP of a buffalo=₹ 20,000.
And Gain=5%
∴ \(SP=CP\; (1+\frac{Gain}{100}\))
\(\Rightarrow 20000=CP\; (1+\frac{5}{100}\))
\(\Rightarrow 20000=CP\;\times (\frac{105}{100}\))
\(\Rightarrow CP=\frac{20000\times100}{105}\)
\(\Rightarrow CP=₹\;\frac{4,00,000}{21}\)
SP of another buffalo=₹ 20,000
And given loss=10%
∴ \(SP=CP\; (1-\frac{loss}{21}\))
\(\Rightarrow 20000=CP\; (1-\frac{10}{100}\))
\(\Rightarrow 20000=CP\;\times (\frac{90}{100}\))
\(\Rightarrow CP=\frac{20000\times100}{90}\)
\(\Rightarrow CP=₹\;\frac{2,00,000}{9}\)
So we have total CP=\(₹\;\frac{4,00,000}{21}\) +\(₹\;\frac{2,00,000}{9}\)
\(=₹\;\frac{12,00,000+14,00,000}{63}\)
\(=₹\;\frac{26,00,000}{63}\)
And we have total SP=₹ 20,000 + ₹ 20,000 =₹ 40,000
Here we see that,SP < CP i.e., it was a loss.
∴ Loss=CP-SP
\(=₹\;\frac{26,00,000}{63}-₹ 40,000\)
\(=₹\;\frac{26,00,000-25,20,000}{63}\)
\(=₹\;\frac{80,000}{63}=₹\;1,269.84\)
Therefore, %Loss=\(\frac{Loss}{CP}\)
=\(\frac{\frac{80,000}{63}}{\frac{26,00,000}{63}}\times 100\)
=\(\frac{80,000}{63}\times\frac{26,00,000}{63}\times100\)
=\(\frac{80}{26}\)%=\(\frac{40}{13}\)%=\(3\frac{1}{13}\)%
Hence, the complete percent loss=\(3\frac{1}{13}\)%.