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Answer :
(i) Given: P = ₹ 60,000, R = 12% p.a. compounded half yearly and n=6 months=\(\frac{6}{12}=\frac{1}2 \;year\)
∴ Simple Interest=\(\frac{P \times R \times n}{100\times 12}\)
=\(\frac{60,000\times 12 }{100}\times \frac{1}2\)
=\(₹ \;3600 \)
Therefore , we have Amount=P+SI
=₹ 60,000 + ₹ 3600
=₹ 63600
So the required amount =₹ 63600
(ii)We have given with :P = ₹ 60,000, R = \(\frac{12}2=6\)% and n=\(1\times 2=2\)half years.
So, we have amount=\(P(1+\frac{R}{100})^n\)
=\(60,000(1+\frac{6}{100})^2\)
=\(60,000(\frac{53}{50})^2\)
=\(60,000\times\frac{53}{50}\times\frac{53}{50}\)
=\(24\times2809=₹\; 67,416\)
Hence the required amount= ₹ 67,416