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# 12.A scooter was bought at ₹ 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year.

We have: Cost price of the scooter = ₹ 42,000
Rate of depreciation = 8% p.a.

Time(n)= 1 year

So, Final value of the scooter = Present value$$\times(1-\frac{R}{100})^n$$

$$=42,000\times(1-\frac{8}{100})$$

$$=42,000\times(\frac{23}{25})$$

$$=1,680\times23=38,640$$

Thus, the value of scooter after 1 year =₹ 38,640.