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Answer :
We have: Cost price of the scooter = ₹ 42,000
Rate of depreciation = 8% p.a.
Time(n)= 1 year
So, Final value of the scooter = Present value\(\times(1-\frac{R}{100})^n\)
\(=42,000\times(1-\frac{8}{100})\)
\(=42,000\times(\frac{23}{25})\)
\(=1,680\times23=38,640\)
Thus, the value of scooter after 1 year =₹ 38,640.