2. Find the remainder when $$x^3 - ax^2 + 6x - a$$ is divided by x - a.
Let $$p(x) = x^3 - ax^2 + 6x - a$$
The zero of $$x - a$$ is x = a i.e. (x - a = 0)
So, $$p(a) = {a}^3 - a{a}^2 + 6{a} - a$$
i.e. $$p(a) = a^3 - a^3 + 6a - a$$
i.e.$$p(a) = 5a$$