We know that Perimeter of square=\(4\times side=4\times 60=240m\)
Also, we have perimeter of rectangle=2(l+b)
Given that these both have same parimeter.
Therefore, we can say that:
perimeter of rectangle=Perimeter of square
\(\Rightarrow 2(80 + b) = 240\)
\(\Rightarrow 160+2b = 240\)
Hence we have, Area of figure (a) i.e, square =\( (side)^2\) = \(60 \times 60 = 3600 m^2\)
Area of figure (b) i.e, rectangle =\( l \times b = 80 \times 40 = 3200 m^2\)
So, the area of figure (a) i.e, square is more than the area of figure (b) i.e, rectangle.