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Answer :

We have,Total area of the garden = Area of the rectangular portion + The sum of the areas of the pair of semi-circles

We have, Length of the rectangle = \(20 – (3.5 + 3.5) = 20 – 7 = 13 m\)

Therefore, area of the rectangle =\( l \times b = 13 \times 7 = 91 m^2\)

Area of two circular ends = \(2\times \frac { 1 }{ 2 }\pi r^2\)

\(= \pi r^2\)

\(= \frac { 22 }{ 7 } \times \frac { 7 }{ 2 } \times \frac { 7 }{ 2 }\)

\(=\frac { 77 }{ 2 } m^2\)

\(= 38.5 m^2\)

Total area = Area of the rectangle + Area of two ends = \(91 m^2 + 38.5 m^2 = 129.5 m^2\)

Total perimeter = Perimeter of the rectangular portion + Perimeter of two circular ends

\(= 2 (l + b) + 2 \times (\pi r) – 2(2r)\)

\(= 2 (13 + 7) + 2(\frac { 22 }{ 7 } \times \frac { 7 }{ 2 }) – 4 \times \frac { 7 }{ 2 }\)

\(= 2 \times 20 + 22 – 14\)

\(= 40 + 22 – 14\)

\(= 48 m\)

So the total perimeter of the figure =48m

- 1.A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area?
- 2.Mrs Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ₹ 55 per \(m^2\).
- 4.A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2? (If required you can split the tiles in whatever way you want to fill up the corners).
- 5.An ant is moving around a few food pieces of different shapes scattered on the floor. For which food-piece would the ant have to take a longer round? Remember, the circumference of a circle can be obtained by using the expression C = \(2\pi r\), where r is the radius of the circle.

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