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Answer :
Area of top trapezium surface of the table=(\frac{1}2\times (sum\; of \;parallel \;sides)\times (distances \;between\; them)\)
\(=\frac{1}2\times(1+1.2)\times0.8 m^2\)
\(=\frac{1}2\times 2.2 \times 0.8 m^2\)
\(=(1.1\times 0.8)=0.88m^2\)
So, the area of top trapezium surface of the table=\(0.88m^2\)