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Answer :
Given, area of trapezium is \(34cm^2\).
Let the required side be x cm.
We know that, area of trapezium=\(\frac{1}2\times (sum\; of \;parallel \;sides)\times (distances \;between\; them)\)
\(34=\frac{1}2\times(10+x)\times 4\)
\(34=2(10+x)\)
\(10+x=17\)
\(x=7\)
Hence, the required side is 7cm.