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# 2.A suitcase of measures $$80 cm \times 48 cm \times 24 cm$$ is to be covered with a tarpaulin cloth. How many metres of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Answer :

Measurement of the suitcase =$$80 cm \times 48 cm \times 24 cm$$

We can say that l = 80 cm, b = 48 cm and h = 24 cm So the total surface area of the suitcase = $$2[lb + bh + hl]$$

$$= 2 (80 \times 48 + 48 \times 24 + 80 \times 24) cm^2$$

$$= 2(3840 + 1152 + 1920) cm^2$$

$$= 2 \times 6912 cm^2 =13824 cm^2$$

We have, Area of tarpaulin = Area of 100 suitcase

Area of Area of 100 suitcase=$$100 \times 13824$$

Also, we have the Area of tarpaulin = $$length \times breadth = l \times 96 = 96l cm^2$$

Equating both we have:

$$96l =100 \times 13824$$

$$\Rightarrow l = 100 \times 144 = 14400 cm = 144 m$$

Hence, the required length of the cloth = 144 m.