2.A suitcase of measures \(80 cm \times 48 cm \times 24 cm\) is to be covered with a tarpaulin cloth. How many metres of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Measurement of the suitcase =\( 80 cm \times 48 cm \times 24 cm\)

We can say that l = 80 cm, b = 48 cm and h = 24 cm So the total surface area of the suitcase = \(2[lb + bh + hl]\)

\(= 2 (80 \times 48 + 48 \times 24 + 80 \times 24) cm^2\)

\(= 2(3840 + 1152 + 1920) cm^2\)

\(= 2 \times 6912 cm^2 =13824 cm^2\)

We have, Area of tarpaulin = Area of 100 suitcase

Area of Area of 100 suitcase=\(100 \times 13824\)

Also, we have the Area of tarpaulin = \(length \times breadth = l \times 96 = 96l cm^2\)

Equating both we have:

\(96l =100 \times 13824\)

\(\Rightarrow l = 100 \times 144 = 14400 cm = 144 m\)

Hence, the required length of the cloth = 144 m.