4.Rukhsar painted the outside of the cabinet of measure \(1 m \times 2 m \times 1.5 m\). How much surface area did she cover if she painted all except the bottom of the cabinet.

Given, l = 2 m, b = 1.5 m, h = 1 m
Area of the surface to be painted = Total surface area of box – Area of base of box

\(= 2 (lb + bh + hl) – lb\)

\(= 2(2 \times 1.5 + 1.5 \times 1 + 1 \times 2) – 2 \times 1\)

\(= 2(3 + 1.5 + 2) – 2\)

\(= 2(6.5) – 2\)

\(= 13 – 2= 11 m^2\)

Hence, the required area = 11 \(m^2\).