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Answer :
Given, l = 2 m, b = 1.5 m, h = 1 m
Area of the surface to be painted = Total surface area of box – Area of base of box
\(= 2 (lb + bh + hl) – lb\)
\(= 2(2 \times 1.5 + 1.5 \times 1 + 1 \times 2) – 2 \times 1\)
\(= 2(3 + 1.5 + 2) – 2\)
\(= 2(6.5) – 2\)
\(= 13 – 2= 11 m^2\)
Hence, the required area = 11 \(m^2\).