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# 5.Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 $$m^2$$ of area is painted.How many cans of paint will she need to paint the room?

Given, l = 15 m, b = 10 m and h = 7 m
Area of the paint in one can = $$100 m^2$$

So,Surface area of a cuboidal hall without bottom = Total surface area – Area of base

$$= 2 (lb + bh + hl) – lb$$

$$= 2 (15 \times 10 + 10 \times 7 + 7 \times 15) – 15 \times 10$$

$$= 2(150 + 70 + 105) – 150$$

$$= 2 (325) – 150$$

$$= 650 – 150= 500 m^2$$

Therefore, the number of cans required =$$\frac { 500 }{ 100 }= 5 cans$$.