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Answer :

Given, l = 15 m, b = 10 m and h = 7 m

Area of the paint in one can = \(100 m^2\)

So,Surface area of a cuboidal hall without bottom = Total surface area – Area of base

\(= 2 (lb + bh + hl) – lb\)

\(= 2 (15 \times 10 + 10 \times 7 + 7 \times 15) – 15 \times 10\)

\(= 2(150 + 70 + 105) – 150\)

\(= 2 (325) – 150\)

\(= 650 – 150= 500 m^2\)

Therefore, the number of cans required =\(\frac { 500 }{ 100 }= 5 cans\).

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