Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Given, l = 15 m, b = 10 m and h = 7 m
Area of the paint in one can = \(100 m^2\)
So,Surface area of a cuboidal hall without bottom = Total surface area – Area of base
\(= 2 (lb + bh + hl) – lb\)
\(= 2 (15 \times 10 + 10 \times 7 + 7 \times 15) – 15 \times 10\)
\(= 2(150 + 70 + 105) – 150\)
\(= 2 (325) – 150\)
\(= 650 – 150= 500 m^2\)
Therefore, the number of cans required =\(\frac { 500 }{ 100 }= 5 cans\).