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Answer :

Given, r = 7 m and h = 3 m.

Sheet required to make a closed cylinder= Total surface area of the cylinder

\(= 2\pi r(r + h)\) sq. units

\(=2\times \frac { 22 }{ 7 } \times 7\times (3+7)\)

\(=2\times \frac { 22 }{ 7 } \times 7\times 10 \)

\(=440 m^2\)

So, the required metal sheet=\(440m^2\)

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