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Answer :
Cylinder B will have a greater volume.
Verification:
Volume of cylinder A=\(\pi r^2h\)
\(=\frac{22}7\times \frac{7}2\times\frac{7}2\times 14\)
\(=539cm^3\)
Volume of cylinder B=\(\pi r^2h\)
\(=\frac{22}7\times7\times7\times 7\)
\(=22\times49=1078cm^3\)
So, we can see that cylinder B has more volume.Hence the assumption was correct.
Now comparing the surface areas of both the cylinders:
Total surface area of cylinder A=\(2\pi r(r+h)\)
\(=2\times\frac{22}7\times\frac{7}2(\frac{7}2+14)\)
\(=2\times\frac{22}7\times\frac{7}2\times \frac{35}2\)
\(=385cm^2\)
Total surface area of cylinder B=\(2\pi r(r+h)\)
\(=2\times\frac{22}7\times7(7+7)\)
\(=2\times\frac{22}7\times7\times 14\)
\(=616cm^2\)
Hence we can observe that cylinder B has more surface area.