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Answer :

Cylinder B will have a greater volume.

Verification:

Volume of cylinder A=\(\pi r^2h\)

\(=\frac{22}7\times \frac{7}2\times\frac{7}2\times 14\)

\(=539cm^3\)

Volume of cylinder B=\(\pi r^2h\)

\(=\frac{22}7\times7\times7\times 7\)

\(=22\times49=1078cm^3\)

So, we can see that cylinder B has more volume.Hence the assumption was correct.

Now comparing the surface areas of both the cylinders:

Total surface area of cylinder A=\(2\pi r(r+h)\)

\(=2\times\frac{22}7\times\frac{7}2(\frac{7}2+14)\)

\(=2\times\frac{22}7\times\frac{7}2\times \frac{35}2\)

\(=385cm^2\)

Total surface area of cylinder B=\(2\pi r(r+h)\)

\(=2\times\frac{22}7\times7(7+7)\)

\(=2\times\frac{22}7\times7\times 14\)

\(=616cm^2\)

Hence we can observe that cylinder B has more surface area.

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