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Answer :
Given, r = 1.5 m, h = 7 m
We have, Volume of the milk tank =\(\pi r^2h\)
\(=\frac { 22 }{ 7 }\times 1.5 \times 1.5 \times 7\)
\(= 22 \times 2.25= 49.50 m^3\)
∴ Volume of milk in litres = \(49.50 \times 1000 L\quad\) [∵ 1 \(m^3\) = 1000 litres]
\(= 49500 L\)
Hence, the required volume of milk = 49500 L.