Let the edge of the cube = x cm
As per the question, edge is doubled so the new edge = 2x cm
(i)We have original surface area =\( 6x^2 cm^2\)
And, the new surface area = \(6(2x)^2 = 6 \times 4\times2 = 24\times2\)
∴ Ratio = \(6x^2 : 24x^2 = 1 : 4\)
Hence, the new surface area will be four times the original surface area.
(ii)We have, original volume of the cube = \(x^3 cm^3\)
And, the new volume of the cube = \((2x)^3 = 8x^3 cm^3\)
∴Ratio =\( x^3 : 8x^3 = 1 : 8\)
Hence, the new volume will be eight times the original volume.