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Answer :

Given,Volume of the reservoir = 108 \(m^3\) = 108000 L [∵1 \(m^3\) = 1000 L]

Water flowing into the reservoir per minute = 60 L

Time taken to fill the reservoir=\(\frac{Volume\;of\;reservoir}{Rate of flowing water}\)

\(=\frac{10800}{60}minutes=1800\;minutes\;
or \;\frac{11800}{60}=30\; hours\)

Hence, the required hour to fill the reservoir = 30 hours.s

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