5.A photograph of a bacteria enlarged 50,000 times attains a length of 5 cm as shown in the diagram. What is the actual length of the bacteria? If the photograph is enlarged 20,000 times only, what would be its enlarged length?

Original length of bacteria=\(\frac{5}{50,000}cm\)

\(=\frac{1}{10,000}=10^{-4}cm\)

Given:Enlargement of 50,000times attains a length of 5 cm.Similarly for enlargement of 20,000 times let the length attained be x

Since, the two quantities are directly proportional so we have

\(\frac{50,000}5=\frac{20,000}{x}\)

\(\Rightarrow 50,000\times x=5\times 20,000\)

\(\Rightarrow x=\frac{5\times 20,000}{50,000}\)

\(\Rightarrow x=2cm\)

So, the required length is 2cm