9.A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time
(i) the length of the shadow cast by another pole 10 m 50 cm high,

(ii) the height of a pole which casts a shadow 5 m long.

Given: Scale of 1 cm represents 18 km.So, let x cm be the distance covered in the map for the drives of 72 km on a road.
We can see that this is the case of direct proportion,So we have

\(\frac{1}{x}=\frac{18}{72}\)

\(\Rightarrow 18x= 1\times72\)

\(\Rightarrow x= \frac{ 1 \times72}{18}\)

\(\Rightarrow x=4cm\)

Hence, for 72km of distance we have 4 cm of scale.