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Factorize :
i)\(12x^2 - 7x + 1\)
ii)\(2x^2 + 7x + 3\)
iii)\(6x^2 + 5x - 6\)
iv)\(3x^2 - x - 4\)


Answer :

i)\(12x^2 - 7x + 1 \)
\( = 12x^2 - 4x -3x + 1\)
(by splitting middle term)

\(= 4x(3x - 1) - 1(3x - 1)\)
\(=(3x - 1)(4x - 1)\)


ii) \(2x^2 + 7x + 3 \)
\(= 2x^2 + 6x + x + 3\)...
(by splitting middle term)

\(= 2x(x + 3) + 1(x + 3)\)
\(=(x + 3)(2x + 1)\)


iii) \(6x^2 + 5x - 6 \)
\( = 6x^2 + 9x - 4x - 6\)
(by splitting middle term)

\(= 3x(2x + 3) - 2(2x + 3)\)
\(=(2x + 3)(3x - 2)\)


iv) \(3x^2 - x - 4 \)
\( = 3x^2 - 4x + 3x - 4\)
(by splitting middle term)

\(= x(3x - 4) + 1(3x - 4)\)
\(=(3x - 4)(x + 1)\)

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