3.Work out the following divisions.
(i) $$(10x – 25) ÷ 5$$

(ii) $$(10x – 25) ÷ (2x – 5)$$

(iii) $$10y (6y + 21) ÷ 5 (2y + 7)$$

(iv) $$9x^2y^2 (3z – 24) ÷ 27xy (z – 8)$$

(v) $$96abc (3a – 12) (56 – 30) ÷ 144 (a – 4) (b – 6)$$

(i)Given:$$(10x – 25) ÷ 5$$

$$=\frac{10x-25}5=\frac{5\times (2x-5)}5$$

$$=2x-5$$

(ii)Given:$$(10x – 25) ÷ (2x – 5)$$

$$=\frac{10x-25}{2x – 5}=\frac{5\times (2x-5)}{2x – 5}$$

$$=5$$

(iii)Given:$$10y (6y + 21) ÷ 5 (2y + 7)$$

$$=\frac{10y (6y + 21)}{ 5 (2y + 7)}=\frac{5\times 2\times y\times 3\times (2y + 7)}{ 5\times (2y + 7)}$$

$$=\frac{2\times y \times 3}1=6y$$

(iv)Given: $$9x^2y^2 (3z – 24) ÷ 27xy (z – 8)$$

$$=\frac{9x^2y^2 (3z – 24)}{ 27xy (z – 8)}=\frac{9\times x^2y^2 \times 3\times (z-8)}{ 9\times 3\times xy \times (z -8)}$$

$$=\frac{xy}1=xy$$

(v)Given: $$96abc (3a – 12) (56 – 30) ÷ 144 (a – 4) (b – 6)$$
$$=\frac{96abc (3a – 12) (56 – 30)}{ 144 (a – 4) (b – 6)}=\frac{48\times 2 \times abc \times 3\times (a-4)\times 5 \times (b-6)}{48\times 3\times (a-4) \times (b-6)}$$

$$=\frac{2 \times abc \times 5}1=10abc$$