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(b) Distance travelled by car.

(i) How much distance did the car cover during the period 7:30 am to 8 am?

(ii) What was the time when the car had covered a distance of 100 km since its start?

(c) Interest on deposits for a year.

(i) Does the graph pass through the origin?

(ii) Use the graph to find the interest on ? 2500 for a year.

(iii) To get an interest of t 280 per year, how much money should be deposited?

Answer :

(a)For plotting the graph take ‘Number of apples, on the x-axis and ‘Cost of apples (in ₹)’ on the y-axis and start marking the given data in order:

(b) (i) The distance covered by the car during the period 7:30 am to 8 am is 120 km – 100 km = 20 km.

(ii) The car had covered a distance of 100 km at 7:30 am, .

(c) (i) Yes

(ii) The interest on ₹ 2500 is ₹ 200 for 1 year.

(iii) To earn the interest of ₹ 280 ,₹ 3500 should be invested.

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