2.

\( \begin{array} \hline \;\;\;4 & A\\ + 9 & 8\\ \hline C\;B & 3\\ \hline \end{array} \)

\( \begin{array} \hline \;\;\;4 & A\\ + 9 & 8\\ \hline C\;B & 3\\ \hline \end{array} \)

We can observe that A+8 gives 3 as the unit's digit to the sum.So it's only possible if A=5.

Now, the sum becomes :

\( \begin{array}
\hline
\;\;\;4 & 5\\
+ 9 & 8\\
\hline
1\;\;4 & 3\\
\hline
\end{array}
\)

By this, we can clearly see that value of B and C as 4 and 1 respectively.

Therefore we got the values as A=5, B=4 and C=1