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Answer :
We can observe that A+8 gives 3 as the unit's digit to the sum.So it's only possible if A=5.
Now, the sum becomes :
\( \begin{array}
\hline
\;\;\;4 & 5\\
+ 9 & 8\\
\hline
1\;\;4 & 3\\
\hline
\end{array}
\)
By this, we can clearly see that value of B and C as 4 and 1 respectively.
Therefore we got the values as A=5, B=4 and C=1