2.
\( \begin{array} \hline \;\;\;4 & A\\ + 9 & 8\\ \hline C\;B & 3\\ \hline \end{array} \)

We can observe that A+8 gives 3 as the unit's digit to the sum.So it's only possible if A=5.

Now, the sum becomes :

\( \begin{array} \hline \;\;\;4 & 5\\ + 9 & 8\\ \hline 1\;\;4 & 3\\ \hline \end{array} \)

By this, we can clearly see that value of B and C as 4 and 1 respectively.

Therefore we got the values as A=5, B=4 and C=1