8.
\( \;\;\begin{array} \hline \;\;\;A & 1\\ + 1 & B\\ \hline \;\;B & 0\\ \hline \end{array} \)

Question

8.
\( \;\;\begin{array} \hline \;\;\;A & 1\\ + 1 & B\\ \hline \;\;B & 0\\ \hline \end{array} \)

Accepted Answer

Answer :

We have condition as:

B+1=0 i.e, B must be 9 to get 0 at unit's digit of the addition.So, we got B=9

Also we have A+1+1(carry)=B

\(\Rightarrow\) A+2=9

\(\Rightarrow\) A=7

Hence, we have A=7 and B=9

8.
\( \;\;\begin{array} \hline \;\;\;A & 1\\ + 1 & B\\ \hline \;\;B & 0\\ \hline \end{array} \)

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8.\( \;\;\begin{array} \hline \;\;\;A & 1\\ + 1 & B\\ \hline \;\;B & 0\\ \hline \end{array} \)

NCERT solutions of related questions for Playing with Numbers

NCERT solutions of related chapters class 8 maths

NCERT solutions of related chapters class 8 science

8.
\( \;\;\begin{array} \hline \;\;\;A & 1\\ + 1 & B\\ \hline \;\;B & 0\\ \hline \end{array} \)