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Answer :
For a number is divisible by 9 we know that the sum of its digits should also divisible by 9.
Here, Sum of the digits of 21y5 = 2 + 1 +y + 5 = 8 + y
So we should have (8 + y) ÷ 9 = 1
\(\Rightarrow 8 + y = 9\)
\(\Rightarrow y = 9 – 8 = 1\)
Hence, the required value of y = 1.