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Answer :
(i) 10, 7, 4…
First term = a = 10,
Common difference = d
= 7 – 10 = 4 – 7 = –3
And n = 30{Because, we need to find 30th term}
\(a_n = a + (n - 1)d\)
= \(a_{30}\)
= 10 + (30 - 1) (-3)
= 10 – 87 = -77
Therefore, the answer is (C).
(ii) -3, \({{-1} \over {2}}\) , 2…
First term = a = –3,
Common difference = d
= \({{-1} \over {2}} - (-3) = 2 - ({{-1} \over {2}}) = {{5} \over {2}}\)
And n = 11 (Because, we need to find 11th term)
= -3 + (11 – 1) \({{5} \over {2}}\)
= -3 + 25 = 22
Therefore 11th term is 22 which means answer is (B).