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Answer :
i.
\({13 \over {3125}} = {13 \over {5^5}} = {13 × 2^5 \over {5^5 × 2^5}} = {13 × 2^5 \over {10^5}} = {416 \over {10^5}} = 0.00416\)
ii.
\({17 \over {8}} = {17 \over {2^3}} = {17 × 5^3 \over {2^3 × 5^3}} = {17 × 5^3 \over {10^3}} = {2125 \over {10^3}} = 2.125\)
iii .
\({15 \over {1600}} = {15 \over {2^6 × 5^2}} = {15 × 5^4 \over {2^6 × 5^2 × 5^4}} = {15 × 5^4 \over {10^6}} = {9375 \over {10^6}} = 0.009375\)
iv.
\({23 \over {2^3 × 5^2}} = {23 × 5^1 \over {2^3 × 5^2 × 5^1}} = {115 \over {10^3}} = 0.115\)
v.\({6 \over {15}} = {2 × 3 \over {3 × 5}} = {2 \over {5}} = {2 × 2 \over {5 × 2}} = {4 \over {10}} = 0.4\)
vi .\({35 \over {50}} = {5 ×7 \over {2 ×5^2}} = {7 \over {2 × 5}} = {7 \over {10}} = 0.7 \)