The \(17^{th}\) term of an AP exceeds its \(10^{th}\) term by 7. Find the common difference.

\( a_{17} = a_{10} + 7\)

Using formula \(a_n = a + (n - 1)d\), to find nth term of arithmetic progression,

\(a_{17}\) = a + 16d… (2)
\(a_{10}\) = a + 9d… (3)

Putting (2) and (3) in equation (1),

a + 16d = a + 9d + 7
\(\Rightarrow \) 7d = 7
\(\Rightarrow \) d = 1