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# The $$17^{th}$$ term of an AP exceeds its $$10^{th}$$ term by 7. Find the common difference.

Answer :

$$a_{17} = a_{10} + 7$$

Using formula $$a_n = a + (n - 1)d$$, to find nth term of arithmetic progression,

$$a_{17}$$ = a + 16d… (2)
$$a_{10}$$ = a + 9d… (3)

Putting (2) and (3) in equation (1),

a + 16d = a + 9d + 7
$$\Rightarrow$$ 7d = 7
$$\Rightarrow$$ d = 1