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Answer :
\( a_{17} = a_{10} + 7\)
Using formula \(a_n = a + (n - 1)d\), to find nth term of arithmetic progression,
\(a_{17}\) = a + 16d… (2)
\(a_{10}\) = a + 9d… (3)
Putting (2) and (3) in equation (1),
a + 16d = a + 9d + 7
\(\Rightarrow \) 7d = 7
\(\Rightarrow \) d = 1